題目 Problem 1 Lemniscate (x2+y2)2=x2−y2(x^2+y^2)^2=x^2-y^2(x2+y2)2=x2−y2 At the point (x,y)=(64,24)(x,y)=\left(\dfrac{\sqrt{6}}{4},\dfrac{\sqrt{2}}{4}\right)(x,y)=(46,42) dydx=?\dfrac{dy}{dx}=?dxdy=? 解答
