題目 Problem Part I Multiple Choice The enclosed area of the curve (x2+y2)2=x2−y2(x^2+y^2)^2=x^2-y^2(x2+y2)2=x2−y2 can be written in the integral form as (A) 2∫0π/4cos2θ dθ2\int_0^{\pi/4}\cos2\theta\,\mathrm{d}\theta2∫0π/4cos2θdθ. (B) 4∫0π/4cos2θ dθ4\int_0^{\pi/4}\cos2\theta\,\mathrm{d}\theta4∫0π/4cos2θdθ. (C) 2∫0π/4cos2θ dθ2\int_0^{\pi/4}\sqrt{\cos2\theta}\,\mathrm{d}\theta2∫0π/4cos2θdθ. (D) 12∫0π/4cos2θ dθ\dfrac{1}{2}\int_0^{\pi/4}\cos2\theta\,\mathrm{d}\theta21∫0π/4cos2θdθ. 解答