題目 Problem (B). Find dydx=(2)‾\dfrac{\mathrm{d}y}{\mathrm{d}x}=\underline{\quad(2)\quad}dxdy=(2) and d2ydx2=(3)‾\dfrac{\mathrm{d}^2y}{\mathrm{d}x^2}=\underline{\quad(3)\quad}dx2d2y=(3) at the point x=1, y=1x=1,\ y=1x=1, y=1 of the curve x3+3x2y+y3=5x^3+3x^2y+y^3=5x3+3x2y+y3=5. 解答