Problem

(J). Let $f(x,y)=\dfrac{1}{(x^2y^2-4x+3y+1)^2}$ and $g(u,v)=f(x(u,v),y(u,v))$, where

$$x(u,v)=u^2-3uv+2v^2$$

and

$$y(u,v)=u^4+3uv^3-4v^4。$$

Find $\dfrac{\partial g}{\partial u}$ at the point $u=1$ and $v=1$. Answer. $\underline{\quad(11)\quad}$.