題目 Problem 4. Find the interval of convergence of the power series ∑n=1∞2n(x−3)n(n+1)!\displaystyle\sum_{n=1}^{\infty}\frac{2n(x-3)^n}{(n+1)!}n=1∑∞(n+1)!2n(x−3)n. Answer : \underline{\quad(1)\quad} 解答