題目 Problem (6) (10 pts) Evaluate the improper integral ∫0∞xtan−1x(1+x2)2 dx\int_{0}^{\infty} \frac{x\tan^{-1}x}{(1+x^2)^2}\,dx∫0∞(1+x2)2xtan−1xdx if it exists. Here tan−1x=arctanx\tan^{-1}x=\arctan xtan−1x=arctanx. 解答