題目 9. (10 points) Find (a,b)(a,b)(a,b) with −12≤b≤12-\dfrac{1}{2} \le b \le \dfrac{1}{2}−21≤b≤21 so that The point P=(1,a,b)P=(1,a,b)P=(1,a,b) is on the surface EEE defined by x2−y4+sin(2z)4=0\frac{x}{2}-\frac{y}{4}+\frac{\sin(2z)}{4}=02x−4y+4sin(2z)=0 The tangent plane to EEE at PPP contains lines l1(t)=P+t(12,1,0)l_1(t)=P+t\left(\frac{1}{2},1,0\right)l1(t)=P+t(21,1,0) l2(t)=P+t(0,2,1)l_2(t)=P+t(0,2,1)l2(t)=P+t(0,2,1) 解答