題目 Problem Part II Answer the following questions Evaluate the definite integral ∫1/21sin−1xx2 dx=(14)‾\int_{1/2}^1\dfrac{\sin^{-1}x}{x^2}\,\mathrm{d}x=\underline{\quad(14)\quad}∫1/21x2sin−1xdx=(14). 解答
